F(x)=5x^2+20x+20

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Solution for F(x)=5x^2+20x+20 equation: 



(F)=5F^2+20F+20

We move all terms to the left:

(F)-(5F^2+20F+20)=0

We get rid of parentheses

-5F^2+F-20F-20=0

We add all the numbers together, and all the variables

-5F^2-19F-20=0

a = -5; b = -19; c = -20;
Δ = b2-4ac
Δ = -192-4·(-5)·(-20)
Δ = -39
Delta is less than zero, so there is no solution for the equation

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